Let's start by taking a look at an example evaluating the square root of $\greenD{25}$:

$\large \sqrt{\greenD{25}} = ,?$

Step 1: Ask, "What number squared equals $\greenD{25}$?"

Step 2: Notice that $\blueD5$ squared equals $\greenD{25}$.

$\large \blueD5^2= \blueD5 \times \blueD5 = \greenD{25}$

The answer

$\large \sqrt{\greenD{25}} = \blueD5$

Here's a question to make sure you understood:

[[โ˜ƒ graded-group 1]]

#Connection to a square

Finding the square root of $\greenD{25}$ is the same as finding the side length of a square with an area of $\greenD{25}$.

[[โ˜ƒ image 1]]

A square with an area of $\greenD{25}$ has a side length of $\blueD{5}$.

[[โ˜ƒ image 2]]

[[โ˜ƒ image 1]]

#Practice Set 1:

[[โ˜ƒ graded-group-set 1]]

###Reflection question

[[โ˜ƒ graded-group 7]]

#Practice Set 2:

[[โ˜ƒ graded-group-set 1]]

#Practice Set 3:

[[โ˜ƒ graded-group-set 1]]